求极限lim(x极限于0)tanx-x\x^2sinx
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求极限lim(x极限于0)tanx-x\x^2sinx
![求极限lim(x极限于0)tanx-x\x^2sinx](/uploads/image/z/5762166-6-6.jpg?t=%E6%B1%82%E6%9E%81%E9%99%90lim%28x%E6%9E%81%E9%99%90%E4%BA%8E0%29tanx-x%5Cx%5E2sinx)
lim(x 0)(tanx-x)/(x*x-sinx)
=lim(x 0)(secx*secx-1)/(2x*sinx+x*x*cosx) (罗比他法则)
=lim(x 0)(tanx*(tanx/x))/(2sinx+xcosx)
=lim(x 0)(tanx/x)*(tanx/(2sinx+xcosx))
又lim(x 0)(tanx/x)=1
原式
=lim(x 0)tanx/(2sinx+xcosx)
=lim(x 0)(secx*secx)/3cosx-xsinx) (罗比他法则)
而lim(x 0)secx=1,lim(x 0)3cosx-xsinx=3,
所以lim(x 0)(secx*secx)/3cosx-xsinx)=1/3
=lim(x 0)(secx*secx-1)/(2x*sinx+x*x*cosx) (罗比他法则)
=lim(x 0)(tanx*(tanx/x))/(2sinx+xcosx)
=lim(x 0)(tanx/x)*(tanx/(2sinx+xcosx))
又lim(x 0)(tanx/x)=1
原式
=lim(x 0)tanx/(2sinx+xcosx)
=lim(x 0)(secx*secx)/3cosx-xsinx) (罗比他法则)
而lim(x 0)secx=1,lim(x 0)3cosx-xsinx=3,
所以lim(x 0)(secx*secx)/3cosx-xsinx)=1/3
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