已知tan2θ=-2根号2,π<2θ<2π.求(2cos²θ/2-sinθ-1)/[根号2sin(π
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/03 13:38:17
已知tan2θ=-2根号2,π<2θ<2π.求(2cos²θ/2-sinθ-1)/[根号2sin(π
![已知tan2θ=-2根号2,π<2θ<2π.求(2cos²θ/2-sinθ-1)/[根号2sin(π](/uploads/image/z/5695222-22-2.jpg?t=%E5%B7%B2%E7%9F%A5tan2%CE%B8%3D-2%E6%A0%B9%E5%8F%B72%2C%CF%80%EF%BC%9C2%CE%B8%EF%BC%9C2%CF%80.%E6%B1%82%282cos%26%23178%3B%CE%B8%2F2-sin%CE%B8-1%29%2F%5B%E6%A0%B9%E5%8F%B72sin%28%CF%80)
w 再答: ![](http://img.wesiedu.com/upload/f/6c/f6caf8b2cdd4d806e53d77306b8232d5.jpg)
再答:![](http://img.wesiedu.com/upload/d/eb/deb1e1a58a060b7a5c531a3b631a2467.jpg)
再答: ʣ�µ���Ӧ�û��˰�?
再问: �����尡
![](http://img.wesiedu.com/upload/f/6c/f6caf8b2cdd4d806e53d77306b8232d5.jpg)
再答:
![](http://img.wesiedu.com/upload/d/eb/deb1e1a58a060b7a5c531a3b631a2467.jpg)
再答: ʣ�µ���Ӧ�û��˰�?
再问: �����尡
已知tan2θ=-2根号2,π<2θ<2π.求(2cos²θ/2-sinθ-1)/[根号2sin(π
已知tan2θ=-2根号2,π/4<θ<π/2.求(2cos²θ/2-sinθ-1)/[根号2sin(π/4+
设tan2θ =-2根号2,2θ∈(π/2,π)求(2cos^2θ-2-sinθ-1)/(sinθ+cosθ)
已知tan2θ=-2根号2,π〈2θ〈2π,求(2cos^2θ/2-sinθ-1)/(根号2sin(θ+9π/4))
已知tan2θ=3/4(π/2<θ<π),求(2cos² ×θ/2+sinθ-1)/√2cos(θ+π/4)的
已知tanθ=根号2,求(1)(cosθ+sinθ)/(cosθ-sinθ);(2)sin²θ-sinθcos
已知tan2θ=3/4(π/2<θ<π),求(2cos^2θ/2+sinθ+10/[√2cos(θ+π/4]
设tan2α=2根号2,α∈(π/2,π),求(cosα-sinα)/sinα+cosα的值,
已知tanθ=-根号2/2,求(2cos平方θ/2-sinθ-1))/根号2sin(θ+π/4)的值?3Q
已知tanθ=根号2,求((2cos平方θ/2)-(sinθ-1))/根号2sin(θ+π/4)的值?
急求已知根号3sinθ-sin(π/2-2θ)/cos(π+θ)×cosθ=1 θ ∈(0,π) 求θ的值
已知tan2α=-2根号2且tanα>1,求[2cos平方α/2-sinα-1]/[根号2sin(π/4+α)]的值