1/(2×1001)+1/(3×1001)-1/(4×1001)+1/(6×1001)-1/(8×1001)
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1/(2×1001)+1/(3×1001)-1/(4×1001)+1/(6×1001)-1/(8×1001)
![1/(2×1001)+1/(3×1001)-1/(4×1001)+1/(6×1001)-1/(8×1001)](/uploads/image/z/5545115-35-5.jpg?t=1%2F%EF%BC%882%C3%971001%EF%BC%89%2B1%2F%EF%BC%883%C3%971001%EF%BC%89-1%2F%EF%BC%884%C3%971001%EF%BC%89%2B1%2F%EF%BC%886%C3%971001%EF%BC%89-1%2F%EF%BC%888%C3%971001%EF%BC%89)
原式=(1/1001)*[(1/2)+(1/3)-(1/4)+(1/6)-(1/8)]
=(1/1001)*{[(1/2)+(1/3)+(1/6)]-[(1/4)+(1/8)]}
=(1/1001)*[1-(3/8)]
=(1/1001)*(5/8)
=5/8008
=(1/1001)*{[(1/2)+(1/3)+(1/6)]-[(1/4)+(1/8)]}
=(1/1001)*[1-(3/8)]
=(1/1001)*(5/8)
=5/8008
1/(2×1001)+1/(3×1001)-1/(4×1001)+1/(6×1001)-1/(8×1001)
计算1/1001+2/1001+3/1001+......+2001/1001=?
在1,2,3,…,1001这1001个数中找出所有满足下面条件的数a来:(1001+a)能整除1001×a.
1/1001+2/1001+3/1001...2001/1001=?
1+2-3+4-5+6-7+8-9+10-11.1000-1001+1002=?(急!)
(1)999²-1001²
(1+3+5+……+1001)-(2+4+6+……1000) 简算
设f(x)=4^x/(4^x+2),求f(1/1001)+f(2/1001)+…+f(1000/1001)
计算:1001分之1+1001分之2+1001分之3+...+1001分之2001
计算 ( 1+1/2)*(1-1/3)*(1+1/4)*(1-1/5)*.*(1+1/1000)*(1-1/1001)
(2000-1)+(1999-2)+(1998-3)+…+(1002-999)+(1001-1000)
计算:(1+1/2)×(1-1/3)×(1+1/4)×(1-1/5)×.×(1+1/1000)×(1-1/1001)