已知函数f(x)=2sin(2wx+π/3)(w>0),T=π,g(x)=cos^2(2x+π/3)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/19 00:05:08
已知函数f(x)=2sin(2wx+π/3)(w>0),T=π,g(x)=cos^2(2x+π/3)
令h(x)=g(x)-f(x),x属于【0,π/2】求函数h(x)的值域
令h(x)=g(x)-f(x),x属于【0,π/2】求函数h(x)的值域
![已知函数f(x)=2sin(2wx+π/3)(w>0),T=π,g(x)=cos^2(2x+π/3)](/uploads/image/z/5406454-46-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D2sin%282wx%2B%CF%80%2F3%29%28w%3E0%29%2CT%3D%CF%80%2Cg%28x%29%3Dcos%5E2%EF%BC%882x%2B%CF%80%2F3%EF%BC%89)
f(x)=2sin(2wx+π/3)(w>0),T=2π/2w=π/w=π,w=1,f(x)=2sin(2x+π/3),
h(x)=g(x)-f(x)=cos^2(2x+π/3)-2sin(2x+π/3)=1-sin^2(2x+π/3)-2sin(2x+π/3)
=-sin^2(2x+π/3)-2sin(2x+π/3)+1=-[sin(2x+π/3)+1]^2+2,
,x属于[0,π/2],0=
h(x)=g(x)-f(x)=cos^2(2x+π/3)-2sin(2x+π/3)=1-sin^2(2x+π/3)-2sin(2x+π/3)
=-sin^2(2x+π/3)-2sin(2x+π/3)+1=-[sin(2x+π/3)+1]^2+2,
,x属于[0,π/2],0=
已知函数f(x)=2sin(2wx+π/3)(w>0),T=π,g(x)=cos^2(2x+π/3)
已知函数f(x)=sin^Wx+√3coswx.cos(π /2-wx) (w>0)且函数y=f(x)的图像相邻两条对称
5已知函数 f(x)=sin(wx+π/6)+sin(wx-π/6)-2cos²(wπ)/2x∈R求函数 f(
已知函数f(x)=sin(wx+π/6)+sin(wx-π/6)-2cos^2 wx/2 w>0 若对任意a属于R,函数
已知函数f(x)=3sin(wx-兀/6)(w>0)和g(x)=2cos(2x+φ)+1
已知函数f(x)=2sin(wx+θ)×cos(wx+θ)+2cos^2(wx+θ)-1,其中0≤θ≤π/2,w>0
已知函数f(x)=6cos^2(3wx/2)+(根号3)sin(3wx)-3.(w>0)
已知函数f(x)=根号3sin(wx+φ)++(w>0,-π/2
(1/2)[紧急求助,高中数学!] 已知函数f(x)=3sin(wx- 派/6) (w〉0)和g(x)=2cos(2x+
函数f(x)=√3sin^(wx/2)+sin(wx/2)cos(wx/2) (w>0)的周期为π,求w的值和函数f(x
已知函数f(X)=sin^2wx+根号3sinwx*sin(wx+π/2)+2cos^2wx,x属于R,在y轴右侧的第一
已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0