log3(2)*log8(9)
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log3(2)*log8(9)
![log3(2)*log8(9)](/uploads/image/z/5381233-25-3.jpg?t=log3%282%29%2Alog8%289%29)
=(lg2/lg3)*(lg9/lg8) (换底)
=(lg2*lg9)/(lg3*lg8)
=(lg2*2lg3)/(lg3*3lg2)
=2/3
=(lg2*lg9)/(lg3*lg8)
=(lg2*2lg3)/(lg3*3lg2)
=2/3
log3(2)*log8(9)
(9/4)^(-1/2)+log8 9*log3 32=
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
log3(2)*log8(9)怎么计算?
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
计算log8底9*log3底32
(log4(3)+log8(3))*log3(2)
log3(2)*log5(3)*log8(5)
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81