设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值
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设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值
![设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值](/uploads/image/z/5365082-2-2.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3Dsin%28wx%2Bq%29%2Bcos%28wx%2Bq%29%28w%3E0%2Cq%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC)
易得f(x)=sin(wx+q)+cos(wx+q)=√2sin(wx+q+π/4),最小正周期为pai得w=2,f(-x)=f(x)得q=π/4,所以=√2sin(2(x+π/4)),求导后f(x)在(0,π/2)单调递减..会了吧.
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