如图,AD=BC,AB=CD,DE=BF,试说明DF=BC.
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/04 03:31:08
如图,AD=BC,AB=CD,DE=BF,试说明DF=BC.
![](http://img.wesiedu.com/upload/7/15/71523f83ea00ad7018952c78fb6a2dd1.jpg)
![](http://img.wesiedu.com/upload/7/15/71523f83ea00ad7018952c78fb6a2dd1.jpg)
![如图,AD=BC,AB=CD,DE=BF,试说明DF=BC.](/uploads/image/z/5314991-23-1.jpg?t=%E5%A6%82%E5%9B%BE%2CAD%3DBC%2CAB%3DCD%2CDE%3DBF%2C%E8%AF%95%E8%AF%B4%E6%98%8EDF%3DBC.)
AD=BC,AB=CD,∴四边形ABCD为平行四边形,∴DE∥BF,∵DE=BF∴四边形DEBF为平行四边形,∴DF=BC
如图,AD=BC,AB=CD,DE=BF,试说明DF=BC.
如图,已知AB=CD,AD=BC,DE=BF,说明BE=DF
如图,ad=bc,ab=cd,de=bf,说明df=be
如图,AD=BC,AB=CD,DE=BF,是说明DF=BE的理由
已知:如图,AD=BC,AB=CD,DE=BF求证:BE=DF
已知如图,AB+AD=BC+CD,求证BF+DF=BE+DE
如图AB=DC,AD=BC,DE=BF求证BE=DF
如图,AD=BC,AB=DC,DE=BF,求证BE=DF
如图,AB=DC,AD=BC,DE=BF,求证:BE=DF
如图,已知:AB=DC,AD=BC,DE=BF.求证:BE=DF.
如图,已知AB=CD,AE=CF,DE=BF,求证AD=BC
如图,AD=BC AD//BC AE=CF,求证(1)DE=BF (2)AB//CD