计算(2x)^-4+(4x^2)^-2 xy(x^-1+y^-1)
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计算(2x)^-4+(4x^2)^-2 xy(x^-1+y^-1)
![计算(2x)^-4+(4x^2)^-2 xy(x^-1+y^-1)](/uploads/image/z/52339-67-9.jpg?t=%E8%AE%A1%E7%AE%97%282x%29%5E-4%2B%284x%5E2%29%5E-2+xy%EF%BC%88x%5E-1%2By%5E-1%EF%BC%89)
原式=1/(16x^4)+1/(16x^4)
=1/(8x^4)
原式=xy)1/x+1/y)
=xy(y+x)/xy
=x+y
=1/(8x^4)
原式=xy)1/x+1/y)
=xy(y+x)/xy
=x+y
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