已知圆M:x2+y2-2mx+4y+m2-1=0与圆N:x2+y2+2x+2y-2=0交于AB两点,且这两点平分圆N的圆
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已知圆M:x2+y2-2mx+4y+m2-1=0与圆N:x2+y2+2x+2y-2=0交于AB两点,且这两点平分圆N的圆周,求圆M的圆心坐标
![已知圆M:x2+y2-2mx+4y+m2-1=0与圆N:x2+y2+2x+2y-2=0交于AB两点,且这两点平分圆N的圆](/uploads/image/z/513058-58-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86M%3Ax2%2By2-2mx%2B4y%2Bm2-1%3D0%E4%B8%8E%E5%9C%86N%3Ax2%2By2%2B2x%2B2y-2%3D0%E4%BA%A4%E4%BA%8EAB%E4%B8%A4%E7%82%B9%2C%E4%B8%94%E8%BF%99%E4%B8%A4%E7%82%B9%E5%B9%B3%E5%88%86%E5%9C%86N%E7%9A%84%E5%9C%86)
AB两点两点平分圆N圆
AB为N圆直径
圆M;
(x-m)^2+(y-n)^2=1+n^2,圆心M(m,n)
圆N:
(x+1)^2+(y+1)^2=4,圆心N(-1,-1)
AB=2R=4
R^2+MN^2=AM^2
4+(m+1)^2+(n+1)^2=n^2+1
M圆心轨迹:
x^2+2x+2y+5=0
AB为N圆直径
圆M;
(x-m)^2+(y-n)^2=1+n^2,圆心M(m,n)
圆N:
(x+1)^2+(y+1)^2=4,圆心N(-1,-1)
AB=2R=4
R^2+MN^2=AM^2
4+(m+1)^2+(n+1)^2=n^2+1
M圆心轨迹:
x^2+2x+2y+5=0
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