(x²+2x²)-(2x+4)²分解因式
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(x²+2x²)-(2x+4)²分解因式
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![(x²+2x²)-(2x+4)²分解因式](/uploads/image/z/5020145-17-5.jpg?t=%28x%26%23178%3B%2B2x%26%23178%3B%EF%BC%89-%EF%BC%882x%2B4%EF%BC%89%26%23178%3B%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F)
题目应该为:
(x²+2x)²-(2x+4)²
=[(x²+2x)+(2x+4)][(x²+2x-(2x+4)]
=(x²+2x+2x+4)(x²+2x-2x-4)
=(x²+4x+4)(x²-4)
=(x+2)²(x+2)(x-2)
(x²+2x)²-(2x+4)²
=[(x²+2x)+(2x+4)][(x²+2x-(2x+4)]
=(x²+2x+2x+4)(x²+2x-2x-4)
=(x²+4x+4)(x²-4)
=(x+2)²(x+2)(x-2)