x-2的绝对值+y-4的绝对值=0,求xy/1+(x+2)(y+2)/1+(x+4)(y+4)/1+...+(x+201
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x-2的绝对值+y-4的绝对值=0,求xy/1+(x+2)(y+2)/1+(x+4)(y+4)/1+...+(x+2010)(y+2010)/1
![x-2的绝对值+y-4的绝对值=0,求xy/1+(x+2)(y+2)/1+(x+4)(y+4)/1+...+(x+201](/uploads/image/z/4719865-49-5.jpg?t=x-2%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%2By-4%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%3D0%2C%E6%B1%82xy%2F1%2B%28x%2B2%29%28y%2B2%29%2F1%2B%28x%2B4%29%28y%2B4%29%2F1%2B...%2B%28x%2B201)
由|x-2|+|y-4|=0,得x=2,y=4,
所以原式=1/(2×4)+1/(4×6)+1/(6×8)+…+1/(2012×2014)
=(1/2)[(1/2-1/4)+(1/4-1/6)+(1/6-1/8)+…+(1/2012-1/2014)]
=(1/2)(1/2--1/2014)=(1/2)(1006/2014)=503/2014.
所以原式=1/(2×4)+1/(4×6)+1/(6×8)+…+1/(2012×2014)
=(1/2)[(1/2-1/4)+(1/4-1/6)+(1/6-1/8)+…+(1/2012-1/2014)]
=(1/2)(1/2--1/2014)=(1/2)(1006/2014)=503/2014.
x-2的绝对值+y-4的绝对值=0,求xy/1+(x+2)(y+2)/1+(x+4)(y+4)/1+...+(x+201
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