tanx=sinx/cosx cos^2=1/1+tan 推倒
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tanx=sinx/cosx cos^2=1/1+tan 推倒
已知tanx=sinx/cosx 推倒cos^2=1/1+tan^2 其中x为钝角
已知tanx=sinx/cosx 推倒cos^2=1/1+tan^2 其中x为钝角
![tanx=sinx/cosx cos^2=1/1+tan 推倒](/uploads/image/z/4685645-29-5.jpg?t=tanx%3Dsinx%2Fcosx+cos%5E2%3D1%2F1%2Btan+%E6%8E%A8%E5%80%92)
1+tan^2x
=1+sin^2x/cos^2
=cos^2x/cos^2x+sin^2/cos^2x
=(cos^2x+sin^2x)/cos^2
1/1+tan^2x
=1/[(cos^2x+sin^2x)/cos^2x]
=cos^2x/cos^2x+sin^2x
因为cos^2x+sin^2x=1
所以cos^2x/cos^2x+sin^2x=cos^2
即cos^2=1/1+tan^2
=1+sin^2x/cos^2
=cos^2x/cos^2x+sin^2/cos^2x
=(cos^2x+sin^2x)/cos^2
1/1+tan^2x
=1/[(cos^2x+sin^2x)/cos^2x]
=cos^2x/cos^2x+sin^2x
因为cos^2x+sin^2x=1
所以cos^2x/cos^2x+sin^2x=cos^2
即cos^2=1/1+tan^2
已知tanx=sinx/cosx 推倒cos^2=1/1+tan
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