根号2/4sin(π/4-x)+根号6/4cos(π/4-x) 化简
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根号2/4sin(π/4-x)+根号6/4cos(π/4-x) 化简
根号2/4就是四分之根号二
根号2/4就是四分之根号二
![根号2/4sin(π/4-x)+根号6/4cos(π/4-x) 化简](/uploads/image/z/4546380-12-0.jpg?t=%E6%A0%B9%E5%8F%B72%2F4sin%EF%BC%88%CF%80%2F4-x%EF%BC%89%2B%E6%A0%B9%E5%8F%B76%2F4cos%EF%BC%88%CF%80%2F4-x%EF%BC%89+%E5%8C%96%E7%AE%80)
√2/4 sin(π/4-x)+√6/4 cos(π/4-x)
=√2/2 [1/2 sin(π/4-x)+√3/2 cos(π/4-x)]
=√2/2 [cosπ/3 sin(π/4-x)+sinπ/3 cos(π/4-x)]
=√2/2 [ sin(π/4-x+π/3)]
=√2/2 [ sin(7π/12-x)]
=√2/2 [ sin(π/2+π/12-x)]
=√2/2 [ cos(π/12-x)]
=√2/2 [1/2 sin(π/4-x)+√3/2 cos(π/4-x)]
=√2/2 [cosπ/3 sin(π/4-x)+sinπ/3 cos(π/4-x)]
=√2/2 [ sin(π/4-x+π/3)]
=√2/2 [ sin(7π/12-x)]
=√2/2 [ sin(π/2+π/12-x)]
=√2/2 [ cos(π/12-x)]
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
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求根号2/4sin(π/4-x)+根号6/4cos(π/4-x)的化简,
已知函数f(x)=cos^4(x)+(2根号3)sinxcosx-sin^4(x)
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