求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n
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求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n
![求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n](/uploads/image/z/454632-24-2.jpg?t=%E6%B1%82%E5%92%8CSn%3D1x2%2B3x2%5E2%2B5x2%5E3%2B%E2%80%A6%2B%EF%BC%882n-1%EF%BC%89x2%5En)
An=(2n-1)x2^n=nx2^(n+1)-2^n,则Sn=[nx2^2x(2^n-1)/(2-1)]-[2x(2^n-1)/2-1]=(2^n-1)(4n-1)
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