化学H2(g)+2/1O2(g)==H2O(g)△H1=-241.8kj/mol
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:化学作业 时间:2024/08/16 12:56:34
化学H2(g)+2/1O2(g)==H2O(g)△H1=-241.8kj/mol
H2O(g)==H2O(l)△H2=-44kj/mol 求H2的燃烧热△H
H2O(g)==H2O(l)△H2=-44kj/mol 求H2的燃烧热△H
![化学H2(g)+2/1O2(g)==H2O(g)△H1=-241.8kj/mol](/uploads/image/z/4492838-38-8.jpg?t=%E5%8C%96%E5%AD%A6H2%EF%BC%88g%29%2B2%2F1O2%28g%29%3D%3DH2O%28g%EF%BC%89%E2%96%B3H1%3D-241.8kj%2Fmol)
H2(g)+2/1O2(g)==H2O(g)△H1=-241.8kj/mol
H2O(g)==H2O(l)△H2=-44kj/mol
两式相加H2(g)+2/1O2(g)==H2O(l)△H1=-285.8kj/mol
H2O(g)==H2O(l)△H2=-44kj/mol
两式相加H2(g)+2/1O2(g)==H2O(l)△H1=-285.8kj/mol
化学H2(g)+2/1O2(g)==H2O(g)△H1=-241.8kj/mol
H2(g)+1/2O2(g)==H2O(g) △H=+242KJ/mol , 2H2(g)+O2(g)==2H2O(g)
(1)CH4(g)+2O2(g)=CO2(g)+2H2O(l),△H1=-890.3kj/mol
高二化学2H2(g)+O2(g)=2H2O(1) △H=571、6kj、mol-1次方 C3H8(g)+5O2(g)=3
已知:2H2(g)+O2(g)=2H2O(l) △H=-571.6kj/mol 2h2(g)+O2(g)=2H2O(g)
已知热化学方程式:H2O(g)=H2(g) O2(g) △H= 241.8kJ·mol-1; H2(g) O2(g)=H
根据下列热化学方程式(1)C(s)+O2(g)=CO2(g)△H1=-393.5kJ/mol(2)H2(g)+12
已知:CH4(g)+2O2(g)=CO2(g)+2H2O(l)△H=-890.3 KJ*mol-1H2(g)+0.5O2
2H2(g)+O2(g)==2H2O(g) △H=-571.6kJ/mol
已知(1)2H2(g)+O2(g)=2H2O(g) △H=-483.6kJ.mol-1
已知2H2(g)+O2(g)=2H2O(g)△H=-484kj/mol 2H2(g)+O2(g)=2H2O(l)△H=-
2H2(g) + O2 (g) = 2H2O(l) △H = - 571.6 kJ/mol