如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……
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如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC.
![如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……](/uploads/image/z/4373110-46-0.jpg?t=%E5%A6%82%E5%9B%BE%EF%BC%9AAB%3DAC%2CAD%3DAE%2CBD%3DCE%2CBD%E4%B8%8ECE%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O.%E6%B1%82%E8%AF%81%3A%E2%88%A0CAB%3D%E2%88%A0EAD%3D%E2%88%A0BOC%E2%80%A6%E2%80%A6)
易证两个大三角形全等,所以,∠C=∠B,∠EAC=∠DAB,因为∠DOC是公共角,所以∠EAD=∠CAB.因为∠CFO和∠BFA是对顶角,所以相等,又∠C=∠B,所以∠BOC=∠CAB,所以:∠CAB=∠EAD=∠BOC.
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC
如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O,求证:角CAB=角EAD=角BOC
如图 AB=AC AD=AE BD=CE,BD与CE相交于点O.求证∠BOC=∠EAD
如图,AB=AC,AD=AE,BD=CE,BD与CE相较与点o,说明∠cab=∠ead=∠boc
如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.
如图,已知AB=AC,AD=AE,∠EAD=∠CAB,BD与CD相较于点O,求证说明:BD=CE.
已知如图等腰三角形ABC与DEF AB=AC AD=AE 且∠CAB=∠EAD 求证CE=BD
初三放缩与相似性已知:如图,线段BD与CE相交于点A,AD:BD=AE:CE求证:AB:AC=AD:AE
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD.求证CE=BD
如图 AB=AC AD=AE BD CE相交于点O
已知:如图,AB=AC,AD=AE,BD,CE相交于点O.(1)求证:OD=OE (2)AO平分∠BAC吗?为什么