已知公差大于零的等差数列an满足a3•a4=48 a2+a5=14 求通项an 若Bn=(根号2)^an 求
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已知公差大于零的等差数列an满足a3•a4=48 a2+a5=14 求通项an 若Bn=(根号2)^an 求数列bn的前n项和Sn
![已知公差大于零的等差数列an满足a3•a4=48 a2+a5=14 求通项an 若Bn=(根号2)^an 求](/uploads/image/z/4279511-47-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%85%AC%E5%B7%AE%E5%A4%A7%E4%BA%8E%E9%9B%B6%E7%9A%84%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97an%E6%BB%A1%E8%B6%B3a3%26%238226%3Ba4%3D48+a2%2Ba5%3D14+%E6%B1%82%E9%80%9A%E9%A1%B9an+%E8%8B%A5Bn%3D%28%E6%A0%B9%E5%8F%B72%EF%BC%89%5Ean+%E6%B1%82)
由 a2+a5=14得到a3+a4=14,又a3*a4=48,∴a3=6,a4=8 ,d=8-6=2,a1=2
通项an=2+2(n-1)=2n,
Bn=(根号2)^an=2^(an/2)=2^n,Bn是等比数列,B1=2,q=2
Sn=2(2^n-1)/(2-1)=2^(n+1)-2
通项an=2+2(n-1)=2n,
Bn=(根号2)^an=2^(an/2)=2^n,Bn是等比数列,B1=2,q=2
Sn=2(2^n-1)/(2-1)=2^(n+1)-2
已知公差大于零的等差数列an满足a3•a4=48 a2+a5=14 求通项an 若Bn=(根号2)^an 求
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