已知数列{an}是公差为d的等差数列,d≠0且a1=0,bn=2^(an)(n属于N*),Sn是{bn}的前n项和,Tn
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已知数列{an}是公差为d的等差数列,d≠0且a1=0,bn=2^(an)(n属于N*),Sn是{bn}的前n项和,Tn=Sn/bn
(n属于N*)(1)求{Tn}的通项公式,(2)当d>0,求极限Tn
(n属于N*)(1)求{Tn}的通项公式,(2)当d>0,求极限Tn
![已知数列{an}是公差为d的等差数列,d≠0且a1=0,bn=2^(an)(n属于N*),Sn是{bn}的前n项和,Tn](/uploads/image/z/4145659-43-9.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E6%98%AF%E5%85%AC%E5%B7%AE%E4%B8%BAd%E7%9A%84%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2Cd%E2%89%A00%E4%B8%94a1%3D0%2Cbn%3D2%5E%28an%29%28n%E5%B1%9E%E4%BA%8EN%2A%EF%BC%89%2CSn%E6%98%AF%EF%BD%9Bbn%EF%BD%9D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%2CTn)
an=(n-1)d Sn=1+2^d+2^2d+.2^(n-1)d=1-2^nd/1-2^d
Tn=1-2^nd/ 2^(n-1)d-2^nd
极限limTn= 2^d/2^d-1
祝你学业进步.
Tn=1-2^nd/ 2^(n-1)d-2^nd
极限limTn= 2^d/2^d-1
祝你学业进步.
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