已知tanα=3/4,则【1-根号2sin(2α-π/4)】/cos^2α=
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已知tanα=3/4,则【1-根号2sin(2α-π/4)】/cos^2α=
![已知tanα=3/4,则【1-根号2sin(2α-π/4)】/cos^2α=](/uploads/image/z/3894763-67-3.jpg?t=%E5%B7%B2%E7%9F%A5tan%CE%B1%3D3%2F4%2C%E5%88%99%E3%80%901-%E6%A0%B9%E5%8F%B72sin%EF%BC%882%CE%B1-%CF%80%2F4%29%E3%80%91%2Fcos%5E2%CE%B1%3D)
tanα=3/4
[1-√2sin(2a-π/4)]/cos²a
=[1-(sin2a-cos2a)]/cos²a
=[2cos²a-2sinacosa]/cos²a
=2-2sina/cosa
=2-2tana
=2-2*(3/4)
=1/2
[1-√2sin(2a-π/4)]/cos²a
=[1-(sin2a-cos2a)]/cos²a
=[2cos²a-2sinacosa]/cos²a
=2-2sina/cosa
=2-2tana
=2-2*(3/4)
=1/2
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