(1+1/2+1/3+.+1/2010)×(1/2+1/3+.+1/2011)-(1+1/2+1/3+.+1/2011)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/06 15:01:47
(1+1/2+1/3+.+1/2010)×(1/2+1/3+.+1/2011)-(1+1/2+1/3+.+1/2011)×(1/2+1/3+.+1/201
![(1+1/2+1/3+.+1/2010)×(1/2+1/3+.+1/2011)-(1+1/2+1/3+.+1/2011)](/uploads/image/z/3892067-35-7.jpg?t=%281%2B1%2F2%2B1%2F3%2B.%2B1%2F2010%29%C3%97%281%2F2%2B1%2F3%2B.%2B1%2F2011%29-%281%2B1%2F2%2B1%2F3%2B.%2B1%2F2011%29)
令1/2+1/3+.+1/2010=a,1/2+1/3+.+1/2011=b,则
原式=(1+a)b-(1+b)a
=b+ab-a-ab
=b-a
=(1/2+1/3+.+1/2010+1/2011)-(1/2+1/3+.+1/2010)
=1/2011
原式=(1+a)b-(1+b)a
=b+ab-a-ab
=b-a
=(1/2+1/3+.+1/2010+1/2011)-(1/2+1/3+.+1/2010)
=1/2011
(1+1/2+1/3+.+1/2010)×(1/2+1/3+.+1/2011)-(1+1/2+1/3+.+1/2011)
(1/2012-1)(1/2011-1)(1/2010-1)...(1/3-1)(1/2-1)咋算
(2011/1-1)(2010/1-1)(2009/1-1)…(3/1-1)(2/1-1)
(1\2012-1)(1\2011-1)(1\2010-1)...(1\3-1)(1\2-1)=?
|1/2011-1/2010|+|1/2011-1/2009|+|1/2009-1/2008|+...+|1/3-1/2
(1/2011*1/2010*1/2009*...1/3*1/2*1)∧2011*(2011*2010*2009*...
计算:(1/2+1/3+...+1/2011)*(1+1/2+1/3+...+1/2010)-(1+1/2+1/3+..
计算(1-1/2-1/3-...-1/2010)*(1/2+1/3+..+1/2011)-(1-1/2-1/3-...-
计算:(1/2-1)(1/3-1)(1/4-1)...(1/2010-1)(1/2011-1)(1/2012-1)
1/1×2+1/2×3+1/3×4+…+1/2010×2011+1/2012×2013
计算:|1/2-1|+|1/3-1/2|+|1/4-1/3|+...+|1/2011-1/2010|+丨12012-1/
(2013/1-1)(2012/1-1)(2011/1-1).(3/1-1)(2/1-1)