若tanα=m 则sin(-5π-α)cos(3x+α)=
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/03 13:27:08
若tanα=m 则sin(-5π-α)cos(3x+α)=
![若tanα=m 则sin(-5π-α)cos(3x+α)=](/uploads/image/z/354611-11-1.jpg?t=%E8%8B%A5tan%CE%B1%3Dm+%E5%88%99sin%28-5%CF%80-%CE%B1%29cos%283x%2B%CE%B1%EF%BC%89%3D)
sin(-5π-α)cos(3π+α)
=sina*(-cosa)
=-sinacosa
=-sinacosa/(sin^2a+cos^2a) 分子分母同时除以 cos^2a
=-tana/(1+tan^2a) tanα=m
=-m/(1+m^2)
=sina*(-cosa)
=-sinacosa
=-sinacosa/(sin^2a+cos^2a) 分子分母同时除以 cos^2a
=-tana/(1+tan^2a) tanα=m
=-m/(1+m^2)
若tanα=m 则sin(-5π-α)cos(3x+α)=
设tan(5π+α)=m,则sin(α−3π)+cos(π−α)sin(−α)−cos(π+α)
若tanα=a,则sin(-5π-α)×cos(3π+α)=?
x=cos(π+α)sin²(3π+α)/tanαtan(π+α)cos三次方(-π-α),则x²+
已知sinα=m-3/m+5,cosα=4-2m/m+5,若α∈(π/2,π),则tanα/2的值
若tan(5π+α)=m,求sin(-α)-cos(π-α)/sin(α-5π)+cos(π+α)的值
若tanα=2,则(5cosα-3sinα)/(3sinα+cosα)=
若tanα=2,则2sin^2α-3sinαcosα+5cos^2α=?
已知tanα=m求sinα cosα
设tan(5π+α)=m,求[sin(-α)-cos(π+α)]的值
已知tanα=1/3,计算(1)sinα+2cosα/5cosα-sinα,(2)1/2sinαcosα+cos^α
若tanα=2,则sinα-cosα/sinα+2cosα=