已知偶函数f(X)在区间【0,+∝)单调增加,则满足f(2x-1)
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已知偶函数f(X)在区间【0,+∝)单调增加,则满足f(2x-1)
![已知偶函数f(X)在区间【0,+∝)单调增加,则满足f(2x-1)](/uploads/image/z/3528425-65-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%81%B6%E5%87%BD%E6%95%B0f%28X%29%E5%9C%A8%E5%8C%BA%E9%97%B4%E3%80%900%2C%2B%E2%88%9D%EF%BC%89%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8A%A0%2C%E5%88%99%E6%BB%A1%E8%B6%B3f%EF%BC%882x-1%29)
case 1:
for
2x-1 >=0
=> x >=1/2
f(2x-1)< f(1/3)
=> 2x-1 < 1/3
x < 2/3
solution for case 1
x >=1/2 and x x > 1/3
solution for case 2
x 1/3
ie 1/3< x < 1/2
solution for f(2x-1)
for
2x-1 >=0
=> x >=1/2
f(2x-1)< f(1/3)
=> 2x-1 < 1/3
x < 2/3
solution for case 1
x >=1/2 and x x > 1/3
solution for case 2
x 1/3
ie 1/3< x < 1/2
solution for f(2x-1)
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