解不等式组 (x+2)(x-2)-(3-x)²<5 (2x-5)²>(x+2)(x-5)+3(x-4
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解不等式组 (x+2)(x-2)-(3-x)²<5 (2x-5)²>(x+2)(x-5)+3(x-4)²
![解不等式组 (x+2)(x-2)-(3-x)²<5 (2x-5)²>(x+2)(x-5)+3(x-4](/uploads/image/z/3411710-62-0.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84+%28x%2B2%29%28x-2%29-%283-x%29%26%23178%3B%EF%BC%9C5+%282x-5%29%26%23178%3B%EF%BC%9E%28x%2B2%29%28x-5%29%2B3%28x-4)
(x+2)(x-2)-(3-x)²<5 (2x-5)² ①
展开得x²-4-(9-6x+x²)<5(4x²-20x+25)
-13+6x<20x²-100x+125
移项得20x²-106x+138>0
因式分解得 2(x-3)(10x-23)>0
①的解集为 x>3 或 x3 或 x
展开得x²-4-(9-6x+x²)<5(4x²-20x+25)
-13+6x<20x²-100x+125
移项得20x²-106x+138>0
因式分解得 2(x-3)(10x-23)>0
①的解集为 x>3 或 x3 或 x
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