先化简,再求值:[(a²-1)/(a²-4)]•[(a+2)/(a²-2a+1
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先化简,再求值:[(a²-1)/(a²-4)]•[(a+2)/(a²-2a+1)]•(a²-4a+4)/a+1,其中a=3.
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解;原式=[(a-1)(a+1)/(a-2)(a+2)]×[(a+2)/(a-1)²]×(a-2)²/(a+1)
=(a-2)/(a-1)
当a=3时,原式=1/2
=(a-2)/(a-1)
当a=3时,原式=1/2
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