已知丨x-8y丨+2(4y-1)²+丨8z-3x丨=0,求x+4y+12z的值
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已知丨x-8y丨+2(4y-1)²+丨8z-3x丨=0,求x+4y+12z的值
![已知丨x-8y丨+2(4y-1)²+丨8z-3x丨=0,求x+4y+12z的值](/uploads/image/z/3207718-46-8.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%A8x-8y%E4%B8%A8%2B2%284y-1%29%26%23178%3B%2B%E4%B8%A88z-3x%E4%B8%A8%3D0%2C%E6%B1%82x%2B4y%2B12z%E7%9A%84%E5%80%BC)
丨x-8y丨+2(4y-1)²+丨8z-3x丨=0
所以x-8y=0 4y-1=0 8z-3x=0
解得:x=2 y=1/4 z=3/4
x+4y+12z
=2+4×1/4+12×3/4
=2+1+9
=12
所以x-8y=0 4y-1=0 8z-3x=0
解得:x=2 y=1/4 z=3/4
x+4y+12z
=2+4×1/4+12×3/4
=2+1+9
=12
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