若1/x-1/y=3,5x+3xy-5y/3x-xy-3y
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若1/x-1/y=3,5x+3xy-5y/3x-xy-3y
1/x-1/y=(y-x)/xy=3
所以y-x=3xy
x-y=-3xy
所以原式=[5(x-y)+3xy]/[3(x-y)-xy]
=[5(-3xy)+3xy]/[3(-3xy)-xy]
=-12xy/(-10xy)
=6/5
所以y-x=3xy
x-y=-3xy
所以原式=[5(x-y)+3xy]/[3(x-y)-xy]
=[5(-3xy)+3xy]/[3(-3xy)-xy]
=-12xy/(-10xy)
=6/5
已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=
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