Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简
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Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简
![Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简](/uploads/image/z/304428-12-8.jpg?t=Sin%28x%2B%CF%80%2F3%29%2B2Sin%28x-%CF%80%2F3%29-%E6%A0%B9%E5%8F%B73%E4%B9%98%E4%BB%A5Cos%282%CF%80%2F3+-x+%29+%E5%8C%96%E7%AE%80%E5%8C%96%E7%AE%80)
=sinx/2+根号3cosx/2+sinx-根号3cosx-根号3(-cosx/2+根号3sinx/2)
=3sinx/2-根号3cosx/2+根号3cosx/2-3sinx/2
=0
=3sinx/2-根号3cosx/2+根号3cosx/2-3sinx/2
=0
Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简
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