已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,说明AB=AC,AD=AE,
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已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,说明AB=AC,AD=AE,
![](http://img.wesiedu.com/upload/9/fc/9fce362c78ba03713a3f9a5b59c8738c.jpg)
![](http://img.wesiedu.com/upload/9/fc/9fce362c78ba03713a3f9a5b59c8738c.jpg)
![已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,说明AB=AC,AD=AE,](/uploads/image/z/2936341-37-1.jpg?t=%E5%B7%B2%E7%9F%A5%E2%88%A0BAC%3D%E2%88%A0DAE%2C%E2%88%A0ABD%3D%E2%88%A0ACE%2CBD%3DCE%2C%E8%AF%B4%E6%98%8EAB%3DAC%2CAD%3DAE%2C)
因为∠BAC=∠DAE,所以∠BAD=∠CAE,又∠ABD=∠ACE,BD=CE,由AAS判断△ABD全等于△ACE,所以AB=AC,AD=AE
已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,说明AB=AC,AD=AE,
如图,已知∠BAC=∠DAE,AB=AC,AD=AE,你能说明BD=CE,∠ABD=∠ACE么?T0T)
如图,已知∠BAC=∠DAE ,∠ABD=∠ACE ,BD=CE 求证:AB=AC,AD=AE
如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
如图,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,那么AB与AC,AD与AE有什么数量关系?
如图,已知AB=AC,AD=AE,BD=CE.试说明:∠BAC=∠DAE
如图已知角BAC=角DAE,角ABD=角ACE,BD=CE.问AB=AC,AD=AE成立吗
已知:如图所示,AB=AC,BD=CE,AD=AE,求证∠BAC=∠DAE
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE
已知:如图,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知:如图6-7,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
如图,已知角BAC=角DAE,角ABD=角ACE BD=CE,求证,AD=AE