根号27+(2-根号6)/根号3-(兀-3)^0
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/23 05:30:38
根号27+(2-根号6)/根号3-(兀-3)^0
根号27+(2-根号6)/根号3-(兀-3)^0
=3√3+(2-√6)√3/3 - 1
=3√3+ 2√3/3-√2 - 1
=11√3/3 -√2 - 1
=3√3+(2-√6)√3/3 - 1
=3√3+ 2√3/3-√2 - 1
=11√3/3 -√2 - 1
根号27+(2-根号6)/根号3-(兀-3)^0
根号3×根号6—根号2×根号27=?
根号2+根号3乘以根号6
计算:根号2分之根号32-根号8;根号27-根号3分之1+根号12;2分之1根号2×3根号3×根号6
根号18-根号9/根号2-(根号3+根号6)/根号3+(根号3-2)的0次方+根号下(1-根号2)的平方
(根号8+二倍的根号6)÷根号2-根号3×根号27
计算:3根号2+根号3-根号8-根号27
(4*根号2-2*根号3)*(根号6-根号3)
|根号6 - 根号2|+|根号2 - 1 | - |3-根号6|
化简:根号(2+根号3)分之根号2+根号6
根号2+根号7<根号3+根号6
计算:1.根号3+2倍根号5+根号7/(根号3+根号5)(根号5+根号7)+根号7+根号11+6/(根号7+3)(根号1