计算:(-3a^n+1b^n)*(1/3ab)*(-a^2c)
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计算:(-3a^n+1b^n)*(1/3ab)*(-a^2c)
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(-3a^n+1b^n)*(1/3ab)*(-a^2c)
=a^n+4 b^n+1 c
=a^n+4 b^n+1 c
计算:(-3a^n+1b^n)*(1/3ab)*(-a^2c)
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(a-b)(a^(n-1)-b^(n-1))=(a-b)^2(a^(n-2)+a^(n-3)b+……+ab^(n-3)+
已知1/n^2+3n=A/n+B/n+3,求ab?
b^3n-1 c^2/a^2n+1×a^2n-1/b^3n-2=
b^3n-1/a^2n-1×c÷b^3n-2/a^2n
计算:(2a-3b)^(4n+1)*(3b-2a)^(6n-1)