初二数学分式化简已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-
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初二数学分式化简
已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-y)的值
先化简,在带入
已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-y)的值
先化简,在带入
![初二数学分式化简已知x-3y=0(xy不等于0),求【(2x+y)/(x²-2xy+y²)】*(x-](/uploads/image/z/2463309-45-9.jpg?t=%E5%88%9D%E4%BA%8C%E6%95%B0%E5%AD%A6%E5%88%86%E5%BC%8F%E5%8C%96%E7%AE%80%E5%B7%B2%E7%9F%A5x-3y%3D0%EF%BC%88xy%E4%B8%8D%E7%AD%89%E4%BA%8E0%EF%BC%89%2C%E6%B1%82%E3%80%90%EF%BC%882x%2By%EF%BC%89%2F%EF%BC%88x%26sup2%3B-2xy%2By%26sup2%3B%EF%BC%89%E3%80%91%2A%EF%BC%88x-)
原式=(2x+y)/(x-y)
x-3y=0 所以x=3y
代入得
原式=(6y+y)/(3y-y)
=7y/2y
=7/2
x-3y=0 所以x=3y
代入得
原式=(6y+y)/(3y-y)
=7y/2y
=7/2
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