英语翻译若函数y=根号下[(a²-1)x²+(a-1)x+2/(a+1)]的定义域为R,求实数a的取
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英语翻译
若函数y=根号下[(a²-1)x²+(a-1)x+2/(a+1)]的定义域为R,求实数a的取值范围.
①a²-1=0,即当a=1时,不等式为2/2=1>=0恒成立,所以a=1符合题意.
②当a²-1≠0时必须……(不好打,省略了^-^)
综上所述,所求a的范围是[1,9]
若函数y=根号下[(a²-1)x²+(a-1)x+2/(a+1)]的定义域为R,求实数a的取值范围.
①a²-1=0,即当a=1时,不等式为2/2=1>=0恒成立,所以a=1符合题意.
②当a²-1≠0时必须……(不好打,省略了^-^)
综上所述,所求a的范围是[1,9]
![英语翻译若函数y=根号下[(a²-1)x²+(a-1)x+2/(a+1)]的定义域为R,求实数a的取](/uploads/image/z/2207197-37-7.jpg?t=%E8%8B%B1%E8%AF%AD%E7%BF%BB%E8%AF%91%E8%8B%A5%E5%87%BD%E6%95%B0y%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%EF%BC%88a%26%23178%3B-1%EF%BC%89x%26%23178%3B%2B%28a-1%29x%2B2%2F%EF%BC%88a%2B1%EF%BC%89%5D%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BAR%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96)
If the function y = root under [(a ² -1) x ² + (a-1) x +2 / (a +1)] of the domain of R,the number of a realistic range of values.
Solution:① a ² -1 = 0,that is,when a = 1,the inequality 2 / 2 = 1> = 0 always true,so a = 1 line meaning of the questions.
② When a ² -1 ≠ 0 must ...seek a range of [1,9]
Solution:① a ² -1 = 0,that is,when a = 1,the inequality 2 / 2 = 1> = 0 always true,so a = 1 line meaning of the questions.
② When a ² -1 ≠ 0 must ...seek a range of [1,9]
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