已知2x-y=10 求代数式[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y的值
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已知2x-y=10 求代数式[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y的值
![已知2x-y=10 求代数式[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y的值](/uploads/image/z/2107277-53-7.jpg?t=%E5%B7%B2%E7%9F%A52x-y%3D10+%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%5B%28x%E2%88%A72%2By%E2%88%A72%29-%28x-y%29%E2%88%A72%2B2y%28x-y%29%5D%C3%B74y%E7%9A%84%E5%80%BC)
[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y
=(2xy+2xy-2y^2)/(4y)
=(2x-y)/2
=10/2
=5
=(2xy+2xy-2y^2)/(4y)
=(2x-y)/2
=10/2
=5
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