怎么解4sinθ-3cosθ+2=0
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怎么解4sinθ-3cosθ+2=0
求sinθ的值
求sinθ的值
![怎么解4sinθ-3cosθ+2=0](/uploads/image/z/20324803-67-3.jpg?t=%E6%80%8E%E4%B9%88%E8%A7%A34sin%CE%B8-3cos%CE%B8%2B2%3D0)
3cosθ=4sinθ+2
cosθ=(4sinθ+2)/3
cos^2θ=(4sinθ+2)^2/9
cos^2θ+sin^2θ=1
(4sinθ+2)^2/9+sin^2θ=1
16sin^2θ+16sinθ+4+9sin^2θ=9
25sin^2θ+16sinθ-5=0
sinθ=(-16+6√21)/50或sinθ=(-16-6√21)/50
cosθ=(4sinθ+2)/3
cos^2θ=(4sinθ+2)^2/9
cos^2θ+sin^2θ=1
(4sinθ+2)^2/9+sin^2θ=1
16sin^2θ+16sinθ+4+9sin^2θ=9
25sin^2θ+16sinθ-5=0
sinθ=(-16+6√21)/50或sinθ=(-16-6√21)/50
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