Y=sin(x+6/π)+sin(x-6/π)+cosx
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/16 15:30:08
Y=sin(x+6/π)+sin(x-6/π)+cosx
![Y=sin(x+6/π)+sin(x-6/π)+cosx](/uploads/image/z/20295000-0-0.jpg?t=Y%3Dsin%28x%2B6%2F%CF%80%29%2Bsin%28x-6%2F%CF%80%29%2Bcosx)
Y=sin(x+6/π)+sin(x-6/π)+cosx
=sinxcosπ/6+cosxsinπ/6+sinxcosπ/6-cosxsinπ/6+cosx
=√3sinx+cosx
=2(√3/2*sinx+1/2*cosx)
=2sin(x+π/6)
=sinxcosπ/6+cosxsinπ/6+sinxcosπ/6-cosxsinπ/6+cosx
=√3sinx+cosx
=2(√3/2*sinx+1/2*cosx)
=2sin(x+π/6)
函数y=2sin(π/6-x)+2cosx(x∈R)的最小值
函数y=cosx•sin(x+π2
1.已知函数y=2sin(x+6分之π)-2cosx
函数y=sin(x+π6
利用cosx=sin(π/2-x),sin'x=cosx,证明(cosx)'=-sinx
函数y=sin^2 x-cosx+3,x属于(2π/3,π/6]的值域为
高中数学f(x)=2sin(x+π/6)-2cosx,x∈[π/2,π].
已知f(x)=2cosx*sin(x+π/6)+√3sinx*cosx-sin^2x.设三角形ABC的内角A满足f(2)
化简:1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα
函数y=sin平方x-cosx,x∈{-π|4,π|4}的值域为
求y=sin平方x+2cosx+1,X属于[0,π/2]值域
已知函数f(x)=2sin(x+π6)-2cosx.