已知x+1/2=y+3/4=x+y/5,求式子3x+2y+1/2x-y+3
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已知x+1/2=y+3/4=x+y/5,求式子3x+2y+1/2x-y+3
![已知x+1/2=y+3/4=x+y/5,求式子3x+2y+1/2x-y+3](/uploads/image/z/2000534-14-4.jpg?t=%E5%B7%B2%E7%9F%A5x%2B1%2F2%3Dy%2B3%2F4%3Dx%2By%2F5%2C%E6%B1%82%E5%BC%8F%E5%AD%903x%2B2y%2B1%2F2x-y%2B3)
已知(x+1)/2=(y+3)/4=(x+y)/5,求式子(3x+2y+1)/(2x-y+3)
由题意得
(x+1)/2=(y+3)/4 ①
(x+1)/2=(x+y)/5 ②
由①得y=2x-1,代入②,得
(x+1)/2=(x+2x-1)/5
解得 x=7,
代入y=2x-1,
解得 y=13
∴(3x+2y+1)/(2x-y+3)
=(21+26+1)/(14-13+3)
=48/4
=12
由题意得
(x+1)/2=(y+3)/4 ①
(x+1)/2=(x+y)/5 ②
由①得y=2x-1,代入②,得
(x+1)/2=(x+2x-1)/5
解得 x=7,
代入y=2x-1,
解得 y=13
∴(3x+2y+1)/(2x-y+3)
=(21+26+1)/(14-13+3)
=48/4
=12
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