已知x=1是方程xx−1+kx−1=xx+1
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已知x=1是方程
+
=
x |
x−1 |
k |
x−1 |
x |
x+1 |
![已知x=1是方程xx−1+kx−1=xx+1](/uploads/image/z/19987123-67-3.jpg?t=%E5%B7%B2%E7%9F%A5x%3D1%E6%98%AF%E6%96%B9%E7%A8%8Bxx%E2%88%921%2Bkx%E2%88%921%EF%BC%9Dxx%2B1)
方程两边都乘(x+1)(x-1),得
x(x+1)+k(x+1)=x(x-1)
∵原方程有增根
∴最简公分母(x+1)(x-1)=0,
解得x=1或-1,把这两个值代入整式方程,
当x=1时,k=-1,
当x=-1时,k值不存在.
x(x+1)+k(x+1)=x(x-1)
∵原方程有增根
∴最简公分母(x+1)(x-1)=0,
解得x=1或-1,把这两个值代入整式方程,
当x=1时,k=-1,
当x=-1时,k值不存在.
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