化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)
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化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)
![化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)](/uploads/image/z/19202388-60-8.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9A%28sin%5E6a%2Bcos%5E6a-1%29+%2F+%28sin%5E4%26ordf%3B%2Bcos%5E4a-1%29)
分子=(sin^2a+cos^2a)^3-3sin^2a*cos^2a(sin^2a+cos^2a)-1
=-3sin^2a*cos^2a
分母=(sin^2a+cos^2a)^2-2sin^2a*cos^2a-1=-2sin^2a*cos^2a
原式的值=分子/分母=3/2
(公式:a^3+b^3=(a+b)^3-3ab*(a+b))
(懂了没有,朋友!)
=-3sin^2a*cos^2a
分母=(sin^2a+cos^2a)^2-2sin^2a*cos^2a-1=-2sin^2a*cos^2a
原式的值=分子/分母=3/2
(公式:a^3+b^3=(a+b)^3-3ab*(a+b))
(懂了没有,朋友!)
1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
化简1-sin^4a-cos^4a/1-sin^6a-cos^6a
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
求值:1-sin^6a-cos^6a/1-sin^4a-cos^4a
(1-sin^4a-cos^4a)/(1-sin^6a-cos^6a)
(1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=?
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
化简 1-sin^4a-cos^4a/cos^2a-cos^4a
(1-sin^6 a-cos^6 a)/(1-sin^4 a-cos^4 a)的化简结果
若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a
证明sin(4A)sin(2A)(1-cos(2A)) cos(4A)cos(2A)(1 cos(2A))=cos(2A
化简Sin A + Sin 2A / 1+cos A +