使(x2+px+8)(x2-3x+q)乘积中不含x2与x3项的p、q的值是( )
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使(x2+px+8)(x2-3x+q)乘积中不含x2与x3项的p、q的值是( )
A. p=0,q=0
B. p=3,q=1
C. p=-3,q=-9
D. p=-3,q=1
A. p=0,q=0
B. p=3,q=1
C. p=-3,q=-9
D. p=-3,q=1
![使(x2+px+8)(x2-3x+q)乘积中不含x2与x3项的p、q的值是( )](/uploads/image/z/18743355-27-5.jpg?t=%E4%BD%BF%EF%BC%88x2%2Bpx%2B8%EF%BC%89%EF%BC%88x2-3x%2Bq%EF%BC%89%E4%B9%98%E7%A7%AF%E4%B8%AD%E4%B8%8D%E5%90%ABx2%E4%B8%8Ex3%E9%A1%B9%E7%9A%84p%E3%80%81q%E7%9A%84%E5%80%BC%E6%98%AF%EF%BC%88%E3%80%80%E3%80%80%EF%BC%89)
∵(x2+px+8)(x2-3x+q),
=x4-3x3+qx2+px3-3px2+pqx+8x2-24x+8q,
=x4+(p-3)x3+(q-3p+8)x2+(pq-24)x+8q.
∵乘积中不含x2与x3项,
∴p-3=0,q-3p+8=0,
∴p=3,q=1.
故选:B.
=x4-3x3+qx2+px3-3px2+pqx+8x2-24x+8q,
=x4+(p-3)x3+(q-3p+8)x2+(pq-24)x+8q.
∵乘积中不含x2与x3项,
∴p-3=0,q-3p+8=0,
∴p=3,q=1.
故选:B.
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