求数学公式:n+(n+1)+(n+2)+(n+3)+……=?
求极限Xn=n/(n^2+1)+n/(n^2+2)+n/(n^2+3)+……+n/(n^2+n),
一个数学公式的由来1^2+2^2+3^2+…+n^2=n(n+1)(2n+1)/6是怎么推出来的,
f(n)=1/(n+1) + 1/(n+2) + 1/(n+3) + …… + 1/(2n),(n∈整数,且n≥2),求
已知Sn=2+5n+8n^2+…+(3n-1)n^n-1(n∈N*)求Sn
(1/(n^2 n 1 ) 2/(n^2 n 2) 3/(n^2 n 3) ……n/(n^2 n n)) 当N越于无穷大
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
用数学归纳法证明:(n+1)+(n+2)+…+(n+n)=n(3n+1)2
f(n)=1/(n+1)+1/(n+2)+1/(n+3)……+1/2n (n∈N*),f(n+1
用数学归纳法证明(n+1)(n+2)…(n+n)=2^n*1*3*…*(2n-1)(n∈N+)在线等
用数学归纳法证明(n+1)(n+2)…(n+n)=2^n*1*3*…*(2n-1)(n∈N+)
数学归纳法证明:1*n+2(n-1)+3(n-2)+…+(n-1)*2+n*1=(1/6)n(n+1)(n+2)
用数学归纳法证明:1*n+2(n-1)+3(n-2)+…+(n-1)*2+n*1=(1/6)n(n+1)(n+2)