学霸help me!i need

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/07/18 20:12:31

学霸help me!i need

（1）因为EF∥AD DE平分∠ADC 所以∠1=∠DEF=∠2 所以DF＝EF 又因为ABCD是平行四边形所以AEFD为菱形（2）由（1）得AEFD是菱形,即AD=AE,且∠A=60º所以ADE为等边三角形连结AF交DE与点O 所以AF⊥DE AF=2AO=2×√(2²-1)=2√3 所以S=AF×DE=2×2√3=4√3

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