lim(x→-1)【ln(tan派x/2)/ln(1-x)】
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/24 23:59:17
lim(x→-1)【ln(tan派x/2)/ln(1-x)】
![lim(x→-1)【ln(tan派x/2)/ln(1-x)】](/uploads/image/z/18275312-56-2.jpg?t=lim%28x%E2%86%92-1%29%E3%80%90ln%28tan%E6%B4%BEx%2F2%29%2Fln%281-x%29%E3%80%91)
求极限x➔-1lim[lntan(πx/2)/ln(1-x)]
此题无解!因为x➔-1时,tan(πx/2)➔tan(-π/2)➔-∞,lntan(-π/2)无定义;而分母ln(1-x)➔ln2.
此题无解!因为x➔-1时,tan(πx/2)➔tan(-π/2)➔-∞,lntan(-π/2)无定义;而分母ln(1-x)➔ln2.
当x趋近于1时 lim[ln(2-x)tan(派/2*x)]
x趋向1负时,求lim【ln(1-x)+tan派/2*x】/cot派*x,谢谢
求极限当x趋向于1负是lim(tan派x/2)/ln(1-x)的值
lim x趋于0 (ln(1+x)-x)/(tan^2 x)
lim(x→0)ln(1-2x)/x
lim(x→0)(cosx)^(1/ln(1+x^2))
lim(x→0)ln(x^2+1)等于
lim(x→0)(ln(1+x^2)/(sec-cosx))
求极限lim (n→+∞)ln(1+x^2)/ln(1+x^4)
lim(x→0) (ln cosx)/[ln(1+x^2)] 等于多少?
lim[cos ln(1+x)-cos ln(x)]
求极限lim Ln(1+x) /x > .< x→0