|x-1|+(x+y)2=0,则xy的值是______.
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|x-1|+(x+y)2=0,则xy的值是______.
![|x-1|+(x+y)2=0,则xy的值是______.](/uploads/image/z/17822291-59-1.jpg?t=%7Cx-1%7C%2B%EF%BC%88x%2By%EF%BC%892%3D0%EF%BC%8C%E5%88%99xy%E7%9A%84%E5%80%BC%E6%98%AF______%EF%BC%8E)
∵|x-1|+(x+y)2=0,
∴x=1,y=-x=-1,
∴xy=-1.
故答案为-1.
∴x=1,y=-x=-1,
∴xy=-1.
故答案为-1.
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