反比例函数问题,读不懂题HI我
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反比例函数问题,读不懂题HI我
M是反比函数y=6/x上移动点,只在0-3范围移动,BM‖x轴,AC‖y轴,当S四边形OADM为6时,求DM于BM关系.
![](http://img.wesiedu.com/upload/8/de/8dede78576085e17e804995c4c485de8.jpg)
M是反比函数y=6/x上移动点,只在0-3范围移动,BM‖x轴,AC‖y轴,当S四边形OADM为6时,求DM于BM关系.
![](http://img.wesiedu.com/upload/8/de/8dede78576085e17e804995c4c485de8.jpg)
![反比例函数问题,读不懂题HI我](/uploads/image/z/17786906-26-6.jpg?t=%E5%8F%8D%E6%AF%94%E4%BE%8B%E5%87%BD%E6%95%B0%E9%97%AE%E9%A2%98%2C%E8%AF%BB%E4%B8%8D%E6%87%82%E9%A2%98HI%E6%88%91)
设D的坐标为(3,y)
S四边形OADM = S矩形BDCO-S三角形OBM-S三角形OAD
= 3y -S三角形OBM-S三角形OAD
S三角形OAD = 3×2/2 = 3
M点的坐标为(6/y,y)
S三角形OBM = y*(6/y)/2 = 3
S四边形OADM = 3y -3 -3 = 6
y = 4
DM = 3/2
BM = 3-3/2 = 3/2
DM = BM
S四边形OADM = S矩形BDCO-S三角形OBM-S三角形OAD
= 3y -S三角形OBM-S三角形OAD
S三角形OAD = 3×2/2 = 3
M点的坐标为(6/y,y)
S三角形OBM = y*(6/y)/2 = 3
S四边形OADM = 3y -3 -3 = 6
y = 4
DM = 3/2
BM = 3-3/2 = 3/2
DM = BM