已知AB=AC AD=AE BD=CE求证 ∠CAB=∠EAD
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/25 21:25:23
已知AB=AC AD=AE BD=CE求证 ∠CAB=∠EAD
![](http://img.wesiedu.com/upload/f/3b/f3b611c628f0ac3b82c247d2616346e9.jpg)
![](http://img.wesiedu.com/upload/f/3b/f3b611c628f0ac3b82c247d2616346e9.jpg)
![已知AB=AC AD=AE BD=CE求证 ∠CAB=∠EAD](/uploads/image/z/17620957-37-7.jpg?t=%E5%B7%B2%E7%9F%A5AB%3DAC+AD%3DAE+BD%3DCE%E6%B1%82%E8%AF%81+%E2%88%A0CAB%3D%E2%88%A0EAD)
∵AB=AC,AD=AE,BD=CE,
∴ΔABD≌ΔACE,
∴∠BAD=∠CAE,
∴∠BAD-∠CAD=∠CAE-∠CAD,
即∠BAC=∠DAE.
∴ΔABD≌ΔACE,
∴∠BAD=∠CAE,
∴∠BAD-∠CAD=∠CAE-∠CAD,
即∠BAC=∠DAE.
如图,已知AB=AC,AD=AE,∠EAD=∠CAB,BD与CD相较于点O,求证说明:BD=CE.
已知如图等腰三角形ABC与DEF AB=AC AD=AE 且∠CAB=∠EAD 求证CE=BD
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC
如图,AB=AC,AD=AE,BD=CE,BD与CE相交与O.求证:∠CAB=∠EAD=∠BOD.
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD.求证CE=BD
如图,AB=AC,AD=AE,BD=CE,BD与CE相交于点O,求证:角CAB=角EAD=角BOC
如图,AB=AC,AD=AE,BD=CE,BD与CE相较与点o,说明∠cab=∠ead=∠boc
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90°.求证:1:求证CE=BD;CE⊥BD.
已知:如图,AB=AD,AC=AE,∠CAE=∠BAD.求证△EAD≌△CAB
如图:AB=AC,AD=AE,BD=CE,BD与CE相交于点O.求证:∠CAB=∠EAD=∠BOC……
如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90°.求证CE=BD;CE⊥BD.
三角形ABC和三角形ADE中,AB=AC,AD=AE.且角CAB=角EAD,求证CE=BD