cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简
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cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简
![cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简](/uploads/image/z/17424214-70-4.jpg?t=cos%28%CF%80-%CE%B1%29tan%282%CF%80-%CE%B1%29tan%28%CF%80-%CE%B1%29%2Fsin%28%CF%80%2B%CE%B1%29+%E5%8C%96%E7%AE%80)
cos(π-α)tan(2π-α)tan(π-α)/sin(π+α)
=-cosα(-tanα)(-tanα)/(-sinα)
=tanαtanα/tanα
=tanα
再问: tan(2π-α)是不是还剩个π
再答: tan(kπ-α)=-tanα k为整数
=-cosα(-tanα)(-tanα)/(-sinα)
=tanαtanα/tanα
=tanα
再问: tan(2π-α)是不是还剩个π
再答: tan(kπ-α)=-tanα k为整数
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