0<β<π/6<α<2π/3,cos(α+π/3)=-5/13 sin(β+2π/3)=3/5 ,求sin(α+β)?
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0<β<π/6<α<2π/3,cos(α+π/3)=-5/13 sin(β+2π/3)=3/5 ,求sin(α+β)?
![0<β<π/6<α<2π/3,cos(α+π/3)=-5/13 sin(β+2π/3)=3/5 ,求sin(α+β)?](/uploads/image/z/17137008-0-8.jpg?t=0%EF%BC%9C%CE%B2%EF%BC%9C%CF%80%EF%BC%8F6%EF%BC%9C%CE%B1%EF%BC%9C2%CF%80%EF%BC%8F3%2Ccos%EF%BC%88%CE%B1%EF%BC%8B%CF%80%EF%BC%8F3%EF%BC%89%3D%EF%BC%8D5%EF%BC%8F13+sin%28%CE%B2%2B2%CF%80%EF%BC%8F3%29%3D3%EF%BC%8F5+%2C%E6%B1%82sin%28%CE%B1%EF%BC%8B%CE%B2%29%3F)
0<β<π/6<α<2π/3
所以:π/2
所以:π/2
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