解分式方程(初二)(1)(2x²+1)\(x+2)=2x (2)(x-2)\(x+2)-1=3\(x²
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解分式方程(初二)
(1)(2x²+1)\(x+2)=2x
(2)(x-2)\(x+2)-1=3\(x²-4)
(3) 3\(x-2 )+x\(2-x) = -2
(1)(2x²+1)\(x+2)=2x
(2)(x-2)\(x+2)-1=3\(x²-4)
(3) 3\(x-2 )+x\(2-x) = -2
![解分式方程(初二)(1)(2x²+1)\(x+2)=2x (2)(x-2)\(x+2)-1=3\(x²](/uploads/image/z/16993912-40-2.jpg?t=%E8%A7%A3%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%EF%BC%88%E5%88%9D%E4%BA%8C%EF%BC%89%EF%BC%881%EF%BC%89%EF%BC%882x%26sup2%3B%2B1%EF%BC%89%5C%EF%BC%88x%2B2%EF%BC%89%3D2x+%EF%BC%882%EF%BC%89%EF%BC%88x-2%EF%BC%89%5C%EF%BC%88x%2B2%EF%BC%89-1%3D3%5C%EF%BC%88x%26sup2)
一
(2x²+1)\(x+2)=2x
(2x²+1)\(x+2)-2x=0
(2x²+1)\(x+2)-2x (x+2)\ (x+2)=0
(2x²+1-2x²-4x)/(x+2)=0
(1-4x)/(x+2)=0
1-4x=0
x=1/4
二
(x-2)\(x+2)-1=3\(x²-4)
((x-2)(x-2))/((x+2)(x-2))-1=3/(x²-4)
(x²-4x+4)/(x²-4)-1=3/(x²-4)
(x²-4x+4)-(x²-4)=3
x²-4x+4-x²+4=3
-4x+8=3
-4x=-5
x=5/4
三
3\(x-2 )+x\(2-x) = -2
3/(x-2)+x/-(x-2)=-2
3/(x-2)-x/(x-2)=-2
(3-x)/(x-2)=-2
3-x=-2(x-2)
3-x=-2x+4
x=1
(2x²+1)\(x+2)=2x
(2x²+1)\(x+2)-2x=0
(2x²+1)\(x+2)-2x (x+2)\ (x+2)=0
(2x²+1-2x²-4x)/(x+2)=0
(1-4x)/(x+2)=0
1-4x=0
x=1/4
二
(x-2)\(x+2)-1=3\(x²-4)
((x-2)(x-2))/((x+2)(x-2))-1=3/(x²-4)
(x²-4x+4)/(x²-4)-1=3/(x²-4)
(x²-4x+4)-(x²-4)=3
x²-4x+4-x²+4=3
-4x+8=3
-4x=-5
x=5/4
三
3\(x-2 )+x\(2-x) = -2
3/(x-2)+x/-(x-2)=-2
3/(x-2)-x/(x-2)=-2
(3-x)/(x-2)=-2
3-x=-2(x-2)
3-x=-2x+4
x=1
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