matlab 编程函数文件求解((2*n)!*x^(2*n+1))/(2^(n!)^2*(2*n+1))之和
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:综合作业 时间:2024/07/13 14:58:08
matlab 编程函数文件求解((2*n)!*x^(2*n+1))/(2^(n!)^2*(2*n+1))之和
![matlab 编程函数文件求解((2*n)!*x^(2*n+1))/(2^(n!)^2*(2*n+1))之和](/uploads/image/z/16848642-66-2.jpg?t=matlab+%E7%BC%96%E7%A8%8B%E5%87%BD%E6%95%B0%E6%96%87%E4%BB%B6%E6%B1%82%E8%A7%A3%28%EF%BC%882%2An%EF%BC%89%21%2Ax%5E%282%2An%2B1%29%29%2F%282%5E%28n%21%29%5E2%2A%282%2An%2B1%29%29%E4%B9%8B%E5%92%8C)
x=2;
n=1:5;
f=sum(factorial(2*n).*x.^(2*n+1)./(pow2(factorial(n).^2.*(2*n+1))));
n=1:5;
f=sum(factorial(2*n).*x.^(2*n+1)./(pow2(factorial(n).^2.*(2*n+1))));
如何编程求解递归函数表达式 L(0)=1,L(1)=1-x;L(n)=(1+2*(n-1)-x)*L(n-1)-(n-1
VB编程n!+(n+1)!+(n+2)!+(n+3)!+……+(n+m)!
2^n/n*(n+1)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
matlab高手,请求函数项级数(-1)^n*sin(pi/2^n*x^n)的连加的和函数
用matlab编程求函数y=1+(-1)^(n+1)/(2*n-1),n=1,2,3,...,200,结果为根号2,
求编程高手,用VB计算出n!+(n+1)!+(n+2)!+...+(n+m)!
lim[n/(n*n+1*1)+n/(n*n+2*2)+...+n/(n*n+n*n)],当x趋向无穷大时,怎么求极限,
求极限lim(x→∞)(1/n+2/n+3/n..+n/n)
求幂级数∑(∞,n=1) [(-1)^n*x^(2n)/n]的和函数
幂级数[∞∑ n=1] [2^(n-1) x^n] / (n!)的和函数
幂级数 (∞∑n=0) {((-1)^n)*(x^2n)}/n!的和函数~