{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z
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{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z
![{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z](/uploads/image/z/1661599-55-9.jpg?t=%7B3x%2B2y%2Bz%3D13+x%2By%2B2z%3D7+2x%2B3y-z%3D12%2C%E6%B1%82x%2Cy%2Cz)
答案为x=2,y=3,z=1; 解答过程为:1式与3式相加可得5x+5y=25,算出x+y=5,代入2式得z=1,再把z=1代入可得x=2,y=3;要采纳哦!
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12
x/2=y/3=z/5 x+3y-z/x-3y+z
3x+2y+z=13 x+y+2z=7 2x+3y-z=12 x=?y=?z=?
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